-16x^2+3x=-70

Solution for -16x^2+3x=-70 equation:

-16x^2+3x=-70

We move all terms to the left:

-16x^2+3x-(-70)=0

We add all the numbers together, and all the variables

-16x^2+3x+70=0

a = -16; b = 3; c = +70;
Δ = b2-4ac
Δ = 32-4·(-16)·70
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-67}{2*-16}=\frac{-70}{-32}
=2+3/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+67}{2*-16}=\frac{64}{-32}
=-2
$